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Jak szybko przekonwertować datę na słowa w programie Excel?

Ogólnie rzecz biorąc, zwykle konwertujemy datę na inne formaty daty lub cyfry w programie Excel, ale czy kiedykolwiek napotkałeś problem z konwersją daty na angielskie słowa, jak pokazano na poniższym zrzucie ekranu? W rzeczywistości nie ma wbudowanej funkcji, która mogłaby to obsłużyć, ale kod VBA.
doc data do słów 1

Konwertuj datę na słowo za pomocą zdefiniowanej funkcji

Konwertuj datę na słowo za pomocą zdefiniowanej funkcji

Oto kod makra, który może ci pomóc w zamianie dat na słowa.

1. Włącz arkusz, którego używasz i naciśnij Alt + F11 klucze do otwarcia Microsoft Visual Basic for Applications okno.

2. kliknij wstawka > Moduł i wklej poniższy kod do skryptu.

VBA: Konwertuj datę na słowo

Function DateToWords(ByVal xRgVal As Date) As String
' Update by Extendoffice on 20240926
    Dim xYear As String
    Dim Hundreds As String
    Dim Decades As String
    Dim xTensArr As Variant
    Dim xOrdArr As Variant
    Dim xCardArr As Variant
    
    ' Initialize arrays
    xOrdArr = Array("First", "Second", "Third", "Fourth", "Fifth", "Sixth", _
                    "Seventh", "Eighth", "Ninth", "Tenth", "Eleventh", "Twelfth", _
                    "Thirteenth", "Fourteenth", "Fifteenth", "Sixteenth", _
                    "Seventeenth", "Eighteenth", "Nineteenth", "Twentieth", _
                    "Twenty-first", "Twenty-second", "Twenty-third", "Twenty-fourth", _
                    "Twenty-fifth", "Twenty-sixth", "Twenty-seventh", "Twenty-eighth", _
                    "Twenty-ninth", "Thirtieth", "Thirty-first")
    
    xCardArr = Array("", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", _
                    "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", _
                    "Seventeen", "Eighteen", "Nineteen")
    
    xTensArr = Array("Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety")
    
    ' Extract year
    xYear = CStr(Year(xRgVal))
    Decades = Mid$(xYear, 3)
    
    ' Handle decades
    If CInt(Decades) < 20 Then
        Decades = xCardArr(CInt(Decades))
    Else
        Decades = xTensArr(CInt(Left$(Decades, 1)) - 2) & "-" & xCardArr(CInt(Right$(Decades, 1)))
    End If
    
    ' Handle hundreds
    Hundreds = Mid$(xYear, 2, 1)
    If CInt(Hundreds) Then
        Hundreds = xCardArr(CInt(Hundreds)) & " Hundred "
    Else
        Hundreds = ""
    End If
    
    ' Construct English representation of the date
    DateToWords = xOrdArr(Day(xRgVal) - 1) & " " & Format$(xRgVal, "mmmm") & " " & _
                  xCardArr(CInt(Left$(xYear, 1))) & " Thousand " & Hundreds & Decades
End Function

doc data do słów 2

3. Zapisz kod i wróć do arkusza, wybierz komórkę, w której wyprowadzisz wynik, wpisz tę formułę = DateToWords (A2) (A2 to data, której używasz), naciśnij Wchodzę i przeciągnij uchwyt automatycznego wypełniania do potrzebnych komórek. Zobacz zrzut ekranu:
doc data do słów 3doc data do słów 4

Odblokuj wygodę natychmiastowej konwersji liczb na słowa w programie Excel dzięki Kutools for Excel's Numbers to Words funkcja, oszczędzając czas i wysiłek w tworzeniu profesjonalnie wyglądających dokumentów bez wysiłku!

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Comments (25)
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Gurleen Singh Chhabra
Gurleen Singh Chhabra
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The spelling of 9th is wrong. It's written Nineth, but it should be Ninth.
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Sunny
Sunny     Gurleen Singh Chhabra
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Thank you for your message. I have corrected and updated the code accordingly. Thank you.
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i
i
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07/08/1998 SEVENTH AUGUST TWENTY HUNDRED NINETY-EIGHT
In this vba have error
convert it1998 but it shows TWENTY HUNDRED NINETY-EIGHT
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MAX
MAX
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07/08/1998 SEVENTH AUGUST NINETEEN HUNDRED NINETY EIGHT
I need dob into words in upper format but i use this micros in excel i got this
07/08/1998 SEVENTH AUGUST ONE THOUSAND NINE HUNDRED NINETY-EIGHT which is not usefull
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Sunny
Sunny     MAX
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Hi, MAX, I have modified the VBA, please try and let me know if it works. Thanks.
Function DateToWords(ByVal xRgVal As Date) As String
'UpdatebyExtendoffice20170926
    Dim xYear As String
    Dim Decades As String
    Dim years As String
    Dim xTensArr As Variant
    Dim xyearArr As Variant
    Dim xOrdArr As Variant
    Dim xCardArr As Variant
    xOrdArr = Array("First", "Second", "Third", _
                   "Fourth", "Fifth", "Sixth", _
                   "Seventh", "Eighth", "Nineth", _
                   "Tenth", "Eleventh", "Twelfth", _
                   "Thirteenth", "Fourteenth", _
                   "Fifteenth", "Sixteenth", _
                   "Seventeenth", "Eighteenth", _
                   "Nineteenth", "Twentieth", _
                   "Twenty-first", "Twenty-second", _
                   "Twenty-third", "Twenty-fourth", _
                   "Twenty-fifth", "Twenty-sixth", _
                   "Twenty-seventh", "Twenty-eighth", _
                   "Twenty-nineth", "Thirtieth", _
                   "Thirty-first")
    xCardArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen")
    xTensArr = Array("Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")
    xYear = CStr(Year(xRgVal))
    
    
      xyearArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen", "Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")

    years = xyearArr(CInt(Year(xRgVal) / 100)) & " Hundred"
    
    Decades = Mid$(xYear, 3)
    If CInt(Decades) < 20 Then
        Decades = xCardArr(CInt(Decades))
    Else
        Decades = xTensArr(CInt(Left$(Decades, 1)) - 2) & "-" & _
                xCardArr(CInt(Right$(Decades, 1)))
    End If

    DateToWords = UCase(xOrdArr(Day(xRgVal) - 1) & _
                  Format$(xRgVal, " mmmm ") & _
                  years & " " & Decades)
End Function
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max     Sunny
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07/08/1998 SEVENTH AUGUST TWENTY HUNDRED NINETY-EIGHT
In this vba have error
convert it1998 but it shows TWENTY HUNDRED NINETY-EIGHT
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Sunny
Sunny     max
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Hi, try this vba:
Function DateToWords(ByVal xRgVal As Date) As String
'UpdatebyExtendoffice20170926
    Dim xYear As String
    Dim Decades As String
    Dim years As String
    Dim xTensArr As Variant
    Dim xyearArr As Variant
    Dim xOrdArr As Variant
    Dim xCardArr As Variant
    xOrdArr = Array("First", "Second", "Third", _
                   "Fourth", "Fifth", "Sixth", _
                   "Seventh", "Eighth", "Nineth", _
                   "Tenth", "Eleventh", "Twelfth", _
                   "Thirteenth", "Fourteenth", _
                   "Fifteenth", "Sixteenth", _
                   "Seventeenth", "Eighteenth", _
                   "Nineteenth", "Twentieth", _
                   "Twenty-first", "Twenty-second", _
                   "Twenty-third", "Twenty-fourth", _
                   "Twenty-fifth", "Twenty-sixth", _
                   "Twenty-seventh", "Twenty-eighth", _
                   "Twenty-nineth", "Thirtieth", _
                   "Thirty-first")
    xCardArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen")
    xTensArr = Array("Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")
    xYear = CStr(Year(xRgVal))
    
    
      xyearArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen", "Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")

    years = xyearArr(Fix(Year(xRgVal) / 100)) & " Hundred"
    
    Decades = Mid$(xYear, 3)
    If CInt(Decades) < 20 Then
        Decades = xCardArr(CInt(Decades))
    Else
        Decades = xTensArr(CInt(Left$(Decades, 1)) - 2) & "-" & _
                xCardArr(CInt(Right$(Decades, 1)))
    End If

    DateToWords = UCase(xOrdArr(Day(xRgVal) - 1) & _
                  Format$(xRgVal, " mmmm ") & _
                  years & " " & Decades)
End Function
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Adil
Adil
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آپ کا بہت شکریہ
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Vivek Sahai
Vivek Sahai
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It is giving the #NAME? Error
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sheynes
sheynes
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I would like to add text to the output, for instance, 1958 gets converted to One Thousand Nineteen Hundred Fifty Eight and I would like it to say One Thousand Nineteen Hundred and Fifty Eight. Can someone give me an example of how I can do this please?
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niraj
niraj
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thank u for helping me . very useful in converting date of birth in word
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JAYANTHI KRISHNAN
JAYANTHI KRISHNAN
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Sir/Madam

It is very useful for me.

Really Amazing and helped to solve the problem within a minute.

Thank you for uploading this document. Very nice
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rahul
rahul
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how to use this code in vb6 for a textbox
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Prajapati Gunvant
Prajapati Gunvant
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date to word in gujarati language avilable ? please answer me. 9427909038
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Sunny
Sunny     Prajapati Gunvant
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I think it does not work for other languages except english.
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